This is basically a calculus course for bioinformatics students. Make sure you try out the tutorial questions before coming to class.

Semester: 2010/2011 (2)

Time: Monday and Wednesday, 12-1.15pm

Venue: SD6, Block D (Bioinformatics Building) ISB, Faculty of Science

Important dates: Mid term test 21 February 2010.

Assessment mode: 60% final exam, 40% mid term tests

Course proforma: SHES 2303 Proforma

Lecture Notes: Week 1(corrected); Week 2; Week 3(corrected) ; Week 4 ; Week 5 ;

Week 6 ; Week 7 ; Week 8 ; Week 9 ; Week 10 & 11 ; Week 12 group presentations; Week 13

Tutorials: Week 1; Week 2; Week 3 (corrected); Week 4 ; Week 5 ; Week 6 ; Week 7 ; Week 8 ; Week 9 ; Week 10&11 ; Week 13 ; Past year paper (2009/2010)

Solutions: Week 1; Week 2 ; Week 3 ; Week 4 ; Week 5 ; Week 6 ; Week 7 ; Mid-semester test ; Week 8 ; Week 9 ; Week 10 & 11; Week 13

How to compute your continuous assessment score (for everyone):

Min{mid-term score + 10, 20} + 20

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## About Tsung Fei

A teacher, researcher in the bioinformatics division at the University of Malaya

Dr Khang, can we see our total carrier marks from the 40% of this course?

Hi Amiruddin, please refer to the computation method at the end of this page.

Thank you..

Dr.Khang, may i know the exact answer of this question?

6÷2(1+2)=？

It is 9.

I read that half of the world say it is 9, the other half say it is 1.

This situation is caused by a confusion of the basic rules of algebraic operations ( x or ÷ FIRST then + or -). Some people recall that you should do whatever that is in a bracket first – but not if there is at least a ÷ or x operation in front of it.

P/S: If you ask R, it will give you the correct result, because it follows the rule STRICTLY.

Thank you Dr.Khang. Now I understand already. It is because the calculator give different answer if press 6/2(1+2) and 6÷2(1+2). Now I’m not confuse already. Thanks a lot.

Dr. Khang, do you offer any elective course for us in next sem?

Hi Share Yuan. No, I’m not teaching any undergrad courses in the coming semester.